Given That Z Is a Standard Normal Random Variable, P(-1 $\le$

Short Answer

Given that Z is a standard normal random variable, P(-1.23 $\le$ Z $\le$ 1.89) is: $\begin{array}{|l|l|}\hline\text { A. } & 0.1903 . \\\hline \text { B. } & 0.9706 . \\\hline \text { C. } & 0.8907 . \\\hline \text { D. } & 0.7803 . \\\hline\end{array}$