Given That Z Is a Standard Normal Variable, the Value $\le$

Short Answer

Given that Z is a standard normal variable, the value z for which P(Z $\le$ z) = 0.2580 is: $\begin{array}{|l|l|}\hline\text { A. } & 0.70 . \\\hline \text { B. } & 0.758 . \\\hline \text { C. } & -0.65 . \\\hline \text { D. } & 0.242 . \\\hline\end{array}$