The Mean of the Exponential Distribution Equals the Mean of the Poisson

Short Answer

The mean of the exponential distribution equals the mean of the Poisson distribution only when the former distribution has a mean equal to: $\begin{array}{|l|l|}\hline\text { A. } & 1.0 . \\\hline \text { B. } & 0.50 \\\hline \text { C. } & 0.25 . \\\hline \text { D. } & \text { any value smaller than } 1.0 \\\hline\end{array}$