Solved

The Joint Probability Distribution of X and Y Is Shown XY1231.30.18.122.15.09.063.05.03.02\begin{array} { c | c c c } & & X \\\hline Y&1&2 & 3 \\\hline 1 & .30 & .18 & .12 \\2 & .15 & .09 & .06 \\3 & .05 & .03 & .02\end{array}

Question 15

Essay

The joint probability distribution of X and Y is shown in the following table. XY1231.30.18.122.15.09.063.05.03.02\begin{array} { c | c c c } & & X \\\hline Y&1&2 & 3 \\\hline 1 & .30 & .18 & .12 \\2 & .15 & .09 & .06 \\3 & .05 & .03 & .02\end{array} a. Determine the marginal probability distributions of X and Y.
b. Are X and Y independent? Explain.
c. Find P(Y = 2 | X = 1).
d. Find the probability distribution of the random variable X + Y.
e. Find E(XY).
f. Find COV(X, Y).

Correct Answer:

verifed

Verified

a.
blured image b. Yes, because p(x, y) =...

View Answer

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions