Ammonium Cyanate (NH₄CNO) Reacts to Form Urea (NH₂CONH₂) $\degree$ C, the Rate Constant, K, Is 3

Multiple Choice

Ammonium cyanate (NH₄CNO) reacts to form urea (NH₂CONH₂) . At 65 $\degree$ C, the rate constant, k, is 3.60 L mol¯¹s¯¹. What is the rate law for this reaction?

A) Rate = 3.60 L mol¯¹s¯¹[NH₄CNO]
B) Rate = 3.60 L mol¯¹s¯¹[NH₄CNO]²
C) Rate = 0.28 mol L¯¹s¯¹[NH₄CNO]
D) Rate = 0.28 mol L¯¹s¯¹[NH₄CNO]²
E) Rate = 3.60 L mol¯¹s¯¹[NH₂CONH₂]¯¹