Potassium Superoxide (KO₂, 71 $\rightarrow$ 4 KOH(s) + 3O₂ (G)
A)26

Multiple Choice

Potassium superoxide (KO₂, 71.10 g/mol) can be used to generate oxygen gas.If the theoretical yield of O₂ (32.00 g/mol) must be 12.0 g, how many grams of KO₂ should be used? Assume the reaction occurs in the presence of excess H₂O (18.02 g/mol) .
4 KO₂(s) + 2 H₂O(l) $\rightarrow$ 4 KOH(s) + 3O₂ (g)

A) 26.7 g
B) 107 g
C) 28.1 g
D) 35.6 g
E) 20.0 g