Multiple Choice
What is the equilibrium concentration of ZN2+(aq) in a solution that is initially 0.0100 M solution in Zn(NO3) 2 at a pH of 13.00?
Zn2+(aq) + 4 OH - (aq) fi Zn(OH) 42 - (aq) Kf=
A) 3.1 * 10-13 M
B) 2.5 * 10-14 M
C) 4.4 * 10-17 M
D) 6.1* 10-10 M
E) 5.0 * 105 M
Correct Answer:
Verified
Correct Answer:
Verified
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