Table 20.3 The following data were obtained from a broth dilution test:

\begin{array} { | c | c | } \hline \begin{array} { c } \text { Concentration } \\\text { of Antibiotic } \\X\end{array} & \text { Growth } \\\hline 2.0 \mu \mathrm { g } / \mathrm { ml } & - \\\hline 1.0 \mu \mathrm { ml } & - \\\hline 0.5 \mu \mathrm { ml } / \mathrm { ml } & - \\\hline 0.25 \mu \mathrm { g } / \mathrm { ml } & + \\\hline 0.125 \mu \mathrm { g } / \mathrm { ml } & + \\\hline 0 & + \\\hline\end{array}

Bacteria from the 0.25 ?g/ml tube were transferred to new growth media containing antibiotic X with the following results:

\begin{array} { | c | c | } \hline \begin{array} { c } \text { Concentration } \\\text { of Antibiotic } \\X\end{array} & \text { Growth } \\\hline 2.0 \mu \mathrm { g } / \mathrm { ml } & - \\\hline 1.0 \mu \mathrm { ml } & + \\\hline 0.5 \mu \mathrm { ml } / \mathrm { ml } & + \\\hline 0.25 \mu \mathrm { g } / \mathrm { ml } & + \\\hline\end{array}

The data in Table 20.3 show that these bacteria
A) were resistant to 1.0 ?g/ml at the start of the experiment.
B) were killed by 0.5 ?g/ml of antibiotic X.
C) are pathogenic.
D) were killed by 0.125 ?g/ml of antibiotic X.
E) developed resistance to antibiotics.

Figure 203 the Substrate for Transpeptidase Used to Synthesize Peptidoglycan

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge