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The Equation r=4xi+4yj=12cos(2π/360)i+12sin(2π/360)j\vec { r } = 4 x \vec { i } + 4 y \vec { j } = 12 \cos ( 2 \pi / 360 ) \vec { i } + 12 \sin ( 2 \pi / 360 ) \vec { j }

Question 75

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The equation r=4xi+4yj=12cos(2π/360)i+12sin(2π/360)j\vec { r } = 4 x \vec { i } + 4 y \vec { j } = 12 \cos ( 2 \pi / 360 ) \vec { i } + 12 \sin ( 2 \pi / 360 ) \vec { j } describes the motion of a particle moving on a circle.Assume x and y are in miles and t is in days.
What is the speed of the particle when it passes through the point (0, 2)?

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