$$( \vec { i } \times 78 \vec { j } ) \cdot \vec { k } = \sqrt { 13 } \vec { i } \cdot ( \sqrt { 13 } \vec { j } \times 6 \vec { k } )$$

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The Answer of $$( \vec { i } \times 78 \vec { j } ) \cdot \vec { k } = \sqrt { 13 } \vec { i } \cdot ( \sqrt { 13 } \vec { j } \times 6 \vec { k } )$$

$( \vec { i } \times 78 \vec { j } ) \cdot \vec { k } = \sqrt { 13 } \vec { i } \cdot ( \sqrt { 13 } \vec { j } \times 6 \vec { k } )$

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(i⃗×78j⃗)⋅k⃗=13i⃗⋅(13j⃗×6k⃗)( \vec { i } \times 78 \vec { j } ) \cdot \vec { k } = \sqrt { 13 } \vec { i } \cdot ( \sqrt { 13 } \vec { j } \times 6 \vec { k } )(i×78j​)⋅k=13​i⋅(13​j​×6k)

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$( \vec { i } \times 78 \vec { j } ) \cdot \vec { k } = \sqrt { 13 } \vec { i } \cdot ( \sqrt { 13 } \vec { j } \times 6 \vec { k } )$

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