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For What Values of P Does the Series $1+9 p+(9 p)^{2}+(9 p)^{3}+\ldots+(9 p)^{n}+$

Question 31

Multiple Choice

For what values of p does the series $1+9 p+(9 p) ^{2}+(9 p) ^{3}+\ldots+(9 p) ^{n}+$ converge, if any?

A) $\frac{-1}{9}$ $<$ $p<$ $\frac{1}{9}$
B) $\frac{-1}{18}$ $<$ $p<$ $\frac{1}{18}$
C) -1 < p < 1
D) $-1 \leq p \leq 1$
E) The series diverges for all values of p.

For What Values of P Does the Series 1+9p+(9p)2+(9p)3+…+(9p)n+1+9 p+(9 p)^{2}+(9 p)^{3}+\ldots+(9 p)^{n}+1+9p+(9p)2+(9p)3+…+(9p)n+

Multiple Choice

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For What Values of P Does the Series $1+9 p+(9 p)^{2}+(9 p)^{3}+\ldots+(9 p)^{n}+$

Correct Answer:
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