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An Object Is in the Shape Drawn Below; Its Boundary y=2x2y=2 x^{2}

Question 68

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An object is in the shape drawn below; its boundary is obtained by rotating the parabola y=2x2y=2 x^{2} (for 0 \le x \le 1) around the y axis.(Units are in centimeters.) Suppose that the density of this object varies with height according to the rule ρ\rho (y) = 12 (2 - y) grams/cm3.Which of the following Riemann sums computes (approximately) the mass in grams of this object?  An object is in the shape drawn below; its boundary is obtained by rotating the parabola  y=2 x^{2}  (for 0  \le x \le  1) around the y axis.(Units are in centimeters.) Suppose that the density of this object varies with height according to the rule  \rho (y) = 12 (2 - y) grams/cm<sup>3</sup>.Which of the following Riemann sums computes (approximately) the mass in grams of this object?   A)   \sum_{y=0}^{2} \pi \cdot y^{2} \cdot 12(2-y)  \Delta y  B)   \sum_{y=0}^{2} \pi \cdot \frac{y^{2}}{4} \cdot 12(2-y)  \Delta y  C)   \sum_{y=0}^{2} \pi \cdot \frac{y}{2} \cdot 12(2-y)  \Delta y  D)   \sum_{y=0}^{2} \pi \cdot y \cdot 12(2-y)  \Delta y


A) y=02πy212(2y) Δy\sum_{y=0}^{2} \pi \cdot y^{2} \cdot 12(2-y) \Delta y
B) y=02πy2412(2y) Δy\sum_{y=0}^{2} \pi \cdot \frac{y^{2}}{4} \cdot 12(2-y) \Delta y
C) y=02πy212(2y) Δy\sum_{y=0}^{2} \pi \cdot \frac{y}{2} \cdot 12(2-y) \Delta y
D) y=02πy12(2y) Δy\sum_{y=0}^{2} \pi \cdot y \cdot 12(2-y) \Delta y

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