For $-4 \leq x \leq 4$ , Define $F(x)=\int_{-4}^{x} \sqrt{16-t^{2}} d t$

Multiple Choice

For $-4 \leq x \leq 4$ , define $F(x) =\int_{-4}^{x} \sqrt{16-t^{2}} d t$ .Find F'(x) .

A) $\sqrt{2 x}$
B) $-\sqrt{2 x}$
C) $-\sqrt{16-x^{2}}$
D) $\sqrt{16-x^{2}}$