Find$\frac{d}{d x} \int_{x}^{1}(1+t)^{3} d t$
A)$(1+x)^{3}$ B)$-(1+x)^{3}$ C)$\frac{1}{3}(1+x)^{4}$ D)$\frac{1}{3}(1+x)^{4}-\frac{16}{3}$

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Find$\frac{d}{d x} \int_{x}^{1}(1+t)^{3} d t$  
A)$(1+x)^{3}$ B)$-(1+x)^{3}$ C)$\frac{1}{3}(1+x)^{4}$ D)$\frac{1}{3}(1+x)^{4}-\frac{16}{3}$

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The Answer of Find$\frac{d}{d x} \int_{x}^{1}(1+t)^{3} d t$  
A)$(1+x)^{3}$ B)$-(1+x)^{3}$ C)$\frac{1}{3}(1+x)^{4}$ D)$\frac{1}{3}(1+x)^{4}-\frac{16}{3}$

Find $\frac{d}{d x} \int_{x}^{1}(1+t)^{3} d t$
A) $(1+x)^{3}$ B) $-(1+x)^{3}$ C) $\frac{1}{3}(1+x)^{4}$ D) $\frac{1}{3}(1+x)^{4}-\frac{16}{3}$

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Find ddx∫x1(1+t)3dt\frac{d}{d x} \int_{x}^{1}(1+t)^{3} d tdxd​∫x1​(1+t)3dt A) (1+x)3(1+x)^{3}(1+x)3 B) −(1+x)3-(1+x)^{3}−(1+x)3 C) 13(1+x)4\frac{1}{3}(1+x)^{4}31​(1+x)4 D) 13(1+x)4−163\frac{1}{3}(1+x)^{4}-\frac{16}{3}31​(1+x)4−316​

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Find $\frac{d}{d x} \int_{x}^{1}(1+t)^{3} d t$
A) $(1+x)^{3}$ B) $-(1+x)^{3}$ C) $\frac{1}{3}(1+x)^{4}$ D) $\frac{1}{3}(1+x)^{4}-\frac{16}{3}$

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