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The Revenue for Selling Q Items Is R(q)=600q2q2R(q)=600 q-2 q^{2} And the Total Cost Is C(q)= 120 + 60q

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The revenue for selling q items is R(q)=600q2q2R(q)=600 q-2 q^{2} and the total cost is C(q)= 120 + 60q.What quantity maximizes profit?

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