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If You Throw a Stone into the Air at an Angle

Question 81

Multiple Choice

If you throw a stone into the air at an angle of θ\theta to the horizontal, it moves along the curve y=xtanθx2100(1+tan2θ) y=x \tan \theta-\frac{x^{2}}{100}\left(1+\tan ^{2} \theta\right) , where y is the height of the stone above the ground, x is the horizontal distance.If the angle θ\theta is fixed, what value of x gives the maximum height? (Your answer will θ\theta .)


A) 50tanθ1+tan2θ\frac{50 \tan \theta}{1+\tan ^{2} \theta}
B) 1+tan2θ50tanθ\frac{1+\tan ^{2} \theta}{50 \tan \theta}
C) tanθ50+50tan2θ\frac{\tan \theta}{50+50 \tan ^{2} \theta}
D) 50+50tan2θtanθ\frac{50+50 \tan ^{2} \theta}{\tan \theta}

Correct Answer:

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