Estimate $\lim _{h \rightarrow 0} \frac{(6+h)^{2}-36}{h}$ To 2 Decimal Places by Substituting Smaller and Smaller Values

Short Answer

Estimate $\lim _{h \rightarrow 0} \frac{(6+h)^{2}-36}{h}$ to 2 decimal places by substituting smaller and smaller values of h.