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Find All Values of X Satisfying the Given Conditions y1=1x+4,y2=1x+3,y3=1x2+7x+12y _ { 1 } = \frac { 1 } { x + 4 } , y _ { 2 } = \frac { 1 } { x + 3 } , y _ { 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }

Question 166

Multiple Choice

Find all values of x satisfying the given conditions.
- y1=1x+4,y2=1x+3,y3=1x2+7x+12y _ { 1 } = \frac { 1 } { x + 4 } , y _ { 2 } = \frac { 1 } { x + 3 } , y _ { 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 } , and the sum of y1y _ { 1 } and 2 times y2y _ { 2 } is y3y _ { 3 } .


A) {4}\{ - 4 \}
B) {0}\{ 0 \}
C) {3}\{ 3 \}
D) \varnothing

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