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Solve for X 0.3%0.3 \% Annually If There Were 5,226,0005,226,000 Residents in the City in 2008 , Find How Many

Question 13

Multiple Choice

Solve for x.
-A city is growing at the rate of 0.3%0.3 \% annually. If there were 5,226,0005,226,000 residents in the city in 2008 , find how many (to the nearest ten-thousand) are living in that city in 2012 . Use y=5,226,000(2.7) 0.003ty = 5,226,000 ( 2.7 ) ^ { 0.003 t } .


A) 5,290,0005,290,000
B) 5,320,0005,320,000
C) 14,110,00014,110,000
D) 170,000

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