Rewrite the Equation in Standard Form $$x ^ { 2 } + y ^ { 2 } + 12 x - 6 y - 164 = 0$$

Multiple Choice

Rewrite the equation in standard form. Find the center and radius of the circle.
- $$x ^ { 2 } + y ^ { 2 } + 12 x - 6 y - 164 = 0$$

A) $( x - 12 ) ^ { 2 } + ( y + 6 ) ^ { 2 } = 16$
center $( 12 , - 6 ) , r = 4$
B) $( x - 12 ) ^ { 2 } + ( y + 6 ) ^ { 2 } = 16$
center $( - 12,6 ) , r = 4$
C) $( x + 12 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = 16$
center $( - 12,6 ) , r = 4$
D) $( x + 12 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = 16$
center $( 12 , - 6 ) , \mathrm { r } = 4$