Rewrite the Equation in Standard Form $$x ^ { 2 } + y ^ { 2 } + 6 x - 8 y - 56 = 0$$

Multiple Choice

Rewrite the equation in standard form. Find the center and radius of the circle.
- $$x ^ { 2 } + y ^ { 2 } + 6 x - 8 y - 56 = 0$$

A) ( x + 3 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 81 center \(( - 3,4 ) , r = 9B) \(( x - 3 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 81 center \(( 3 , - 4 ) , r = 9C) \(( x - 4 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 81center \(( 4 , - 3 ) , \ { r } = 9
D) ( x + 3 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 81 center \(( - 3,4 ) , r = 81