Use the Formulas $\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$ And $\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$ To Find the Sum in Terms
Of

Short Answer

Use the formulas $\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$ and
$\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$ to find the sum in terms
of $\text { n. } \sum_{k=1}^{n}\left(3 k^{2}-5 k+7\right)$