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    Precalculus Graphical Numerical Algebraic
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    Exam 8: Analytic Geometry in Two and Three Dimensions
  5. Question
    Identify the Type of Conic Given by the Equation\(2 x^{2}-x y+3 y^{2}-x-4 y-6=0\)
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Identify the Type of Conic Given by the Equation 2x2−xy+3y2−x−4y−6=02 x^{2}-x y+3 y^{2}-x-4 y-6=02x2−xy+3y2−x−4y−6=0

Question 27

Question 27

Short Answer

Identify the type of conic given by the equation 2x2−xy+3y2−x−4y−6=02 x^{2}-x y+3 y^{2}-x-4 y-6=02x2−xy+3y2−x−4y−6=0

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