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Prove the Identity sin⁡3A−cos⁡3Asin⁡2A−cos⁡2A=2+sin⁡2A2(sin⁡A+cos⁡A)\frac{\sin ^{3} A-\cos ^{3} A}{\sin ^{2} A-\cos ^{2} A}=\frac{2+\sin 2 A}{2(\sin A+\cos A)}

Question 21

Essay

Prove the identity:
sin⁡3A−cos⁡3Asin⁡2A−cos⁡2A=2+sin⁡2A2(sin⁡A+cos⁡A)\frac{\sin ^{3} A-\cos ^{3} A}{\sin ^{2} A-\cos ^{2} A}=\frac{2+\sin 2 A}{2(\sin A+\cos A)}

Correct Answer:

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