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The Following MINITAB Output Display Presents the Results of a Hypothesis

Question 5

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The following MINITAB output display presents the results of a hypothesis test on the difference between two proportions.
Test and CI for Two Proportions: P1, P2
 Variable XN Sample P  P1 431070.40186916 P2 36950.37894737\begin{array} { l r r r } \text { Variable } & \mathrm { X } & \mathrm { N } & \text { Sample P } \\ \text { P1 } & 43 & 107 & 0.40186916 \\ \text { P2 } & 36 & 95 & 0.37894737 \end{array}
Difference =p(P1)=p(P2)= \mathrm { p } ( \mathrm { P } 1 ) = \mathrm { p } ( \mathrm { P } 2 )
Estimate for differencę.02292179
95%95 \% CI for difference:(-0.11191015, 0.15775373)
T-Test of difference =0(= 0 ( vs not =Z)=0.33320523= \mathbb { Z } ) = 0.33320523 \quad P-Value =0.7389795= 0.7389795
Can you reject H0H _ { 0 } rejected at the α=0.05\alpha = 0.05 level?

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