Solve
-A Person Is Standing on the Top of a Building

Multiple Choice

Solve.
-A person is standing on the top of a building 50 feet above the ground. They project an object upward with an initial velocity of 40 feet per second. The object's distance above the ground, $\mathrm { d }$ , after $t$ seconds may be found by the formula $d = - 16 t ^ { 2 } + 40 t + 50$ . What is the maximum height the object will reach. How much time does it take to fall back to the ground? Assume that it takes the same time for going up and coming down.

A) Maximum height $= 75 \mathrm { ft }$ ; time to reach ground $= 1.25$ seconds
B) Maximum height $= 75 \mathrm { ft }$ ; time to reach ground $= 2.5$ seconds
C) Maximum height $= 50 \mathrm { ft }$ ; time to reach ground $= 2.5$ seconds
D) Maximum height $= 50 \mathrm { ft }$ ; time to reach ground $= 1.25$ seconds