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Solve the Problem h(t)=16t2+128t+1040h ( t ) = - 16 t ^ { 2 } + 128 t + 1040

Question 331

Multiple Choice

Solve the problem.
-A pebble is hurled upward from the top of a 1040-foot-tall building with an initial velocity of 128 feet per second. Neglecting air resistance, the height h(t) in feet of the pebble after t seconds is given by the polynomial function h(t) =16t2+128t+1040h ( t ) = - 16 t ^ { 2 } + 128 t + 1040 a. Find the height of the pebble when t=1t = 1 .
b. Find the height of the pebble when t=5.1t = 5.1 .
c. Factor the polynomial 16t2+128t+1040- 16 \mathrm { t } ^ { 2 } + 128 \mathrm { t } + 1040 .
d. When will the pebble hit the ground?


A) a. 896ft896 \mathrm { ft }
b. 1276.64ft1276.64 \mathrm { ft }
c. 16(t13) (t+5) - 16 ( t - 13 ) ( t + 5 )
d. 13sec13 \mathrm { sec }
B) a. 896ft896 \mathrm { ft }
b. 28.96ft- 28.96 \mathrm { ft }
c. 16(t+13) (t5) - 16 ( t + 13 ) ( t - 5 )
d. 5sec5 \mathrm { sec }
C) a. 1152ft1152 \mathrm { ft }
b. 28.96ft- 28.96 \mathrm { ft }
c. 16(t+13) (t5) - 16 ( t + 13 ) ( t - 5 )
d. 5sec5 \mathrm { sec }
D) a. 1152ft1152 \mathrm { ft }
b. 1276.64ft1276.64 \mathrm { ft }
c. 16(t13) (t+5) - 16 ( t - 13 ) ( t + 5 )
d. 13sec13 \mathrm { sec }

Correct Answer:

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