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Solve the Compound Inequality 45x+10 or 3x<12\frac { 4 } { 5 } x + 1 \leq 0 \text { or } - 3 x < - 12

Question 227

Multiple Choice

Solve the compound inequality. Give the answer in interval notation.
- 45x+10 or 3x<12\frac { 4 } { 5 } x + 1 \leq 0 \text { or } - 3 x < - 12


A) (,4) ( - \infty , 4 )
B) (,54](4,) \left( - \infty , \frac { 5 } { 4 } \right] \cup ( 4 , \infty )
C) (,45](9,) \left( - \infty , \frac { 4 } { 5 } \right] \cup ( - 9 , \infty )
D) [54,4) \left[ \frac { 5 } { 4 } , 4 \right)

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