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Sketch the Graph of the Equation x=y2+12y+31x=y^{2}+12 y+31 A)  vertex (5,6)\text { vertex } ( - 5,6 )

Question 36

Multiple Choice

Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.
x=y2+12y+31x=y^{2}+12 y+31
 Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.  x=y^{2}+12 y+31    A)   \text { vertex } ( - 5,6 )      B)   \text { vertex } ( 5 , - 6 )      C)   \text { vertex } ( - 6 , - 5 )      D)   \text { vertex } ( - 5 , - 6 )


A)  vertex (5,6) \text { vertex } ( - 5,6 )
 Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.  x=y^{2}+12 y+31    A)   \text { vertex } ( - 5,6 )      B)   \text { vertex } ( 5 , - 6 )      C)   \text { vertex } ( - 6 , - 5 )      D)   \text { vertex } ( - 5 , - 6 )

B)  vertex (5,6) \text { vertex } ( 5 , - 6 )
 Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.  x=y^{2}+12 y+31    A)   \text { vertex } ( - 5,6 )      B)   \text { vertex } ( 5 , - 6 )      C)   \text { vertex } ( - 6 , - 5 )      D)   \text { vertex } ( - 5 , - 6 )

C)  vertex (6,5) \text { vertex } ( - 6 , - 5 )
 Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.  x=y^{2}+12 y+31    A)   \text { vertex } ( - 5,6 )      B)   \text { vertex } ( 5 , - 6 )      C)   \text { vertex } ( - 6 , - 5 )      D)   \text { vertex } ( - 5 , - 6 )

D)  vertex (5,6) \text { vertex } ( - 5 , - 6 )
 Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.  x=y^{2}+12 y+31    A)   \text { vertex } ( - 5,6 )      B)   \text { vertex } ( 5 , - 6 )      C)   \text { vertex } ( - 6 , - 5 )      D)   \text { vertex } ( - 5 , - 6 )

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