Solved

The Graph of the Equation Is a Circle $x^{2}+y^{2}+6 x+6 y+14=0$

Question 84

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+y^{2}+6 x+6 y+14=0$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}+6 x+6 y+14=0 A) center ( - 3,3 ) ; radius = 2 B) center ( 3,3 ) ; radius = 2 C) center ( 3 , - 3 ) ; radius = 2 D) center ( - 3 , - 3 ) ; radius = 2$

A) center $( - 3,3 )$ ; radius $= 2$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}+6 x+6 y+14=0 A) center ( - 3,3 ) ; radius = 2 B) center ( 3,3 ) ; radius = 2 C) center ( 3 , - 3 ) ; radius = 2 D) center ( - 3 , - 3 ) ; radius = 2$
B) center $( 3,3 )$ ; radius $= 2$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}+6 x+6 y+14=0 A) center ( - 3,3 ) ; radius = 2 B) center ( 3,3 ) ; radius = 2 C) center ( 3 , - 3 ) ; radius = 2 D) center ( - 3 , - 3 ) ; radius = 2$
C) center $( 3 , - 3 )$ ; radius $= 2$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}+6 x+6 y+14=0 A) center ( - 3,3 ) ; radius = 2 B) center ( 3,3 ) ; radius = 2 C) center ( 3 , - 3 ) ; radius = 2 D) center ( - 3 , - 3 ) ; radius = 2$
D) center $( - 3 , - 3 )$ ; radius $= 2$
$The graph of the equation is a circle. Find the center and the radius, and then graph the circle. - x^{2}+y^{2}+6 x+6 y+14=0 A) center ( - 3,3 ) ; radius = 2 B) center ( 3,3 ) ; radius = 2 C) center ( 3 , - 3 ) ; radius = 2 D) center ( - 3 , - 3 ) ; radius = 2$

The Graph of the Equation Is a Circle x2+y2+6x+6y+14=0x^{2}+y^{2}+6 x+6 y+14=0x2+y2+6x+6y+14=0

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

The Graph of the Equation Is a Circle $x^{2}+y^{2}+6 x+6 y+14=0$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge