Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$

Short Answer

Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) If $S = \{ x \mid 1 \leq x \leq 6 \}$
, find $g ( S )$ .
(b) If $T$ ={2} , find $g ^ { - 1 } ( T )$