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An Equation of a Parabola Is Given y2+16x4y+52=0y ^ { 2 } + 16 x - 4 y + 52 = 0

Question 124

Multiple Choice

An equation of a parabola is given. Write the equation of the parabola in standard form, and identify the
vertex and the equation of the directrix.
- y2+16x4y+52=0y ^ { 2 } + 16 x - 4 y + 52 = 0


A) (y+2) 2=16(x3) ( y + 2 ) ^ { 2 } = - 16 ( x - 3 )
vertex: (3,2) ( - 3,2 ) ; focus: (7,2) ( 7,2 )
B) (y+2) 2=16(x3) ( y + 2 ) ^ { 2 } = - 16 ( x - 3 )
vertex: (3,2) ( 3 , - 2 ) ; focus: (7,2) ( 7 , - 2 )
C) (y2) 2=16(x+3) ( y - 2 ) ^ { 2 } = - 16 ( x + 3 )
vertex: (3,2) ( - 3,2 ) ; focus: (7,2) ( - 7,2 )
D) (y2) 2=16(x+3) ( y - 2 ) ^ { 2 } = - 16 ( x + 3 )
vertex: (3,2) ( 3 , - 2 ) ; focus: (7,2) ( - 7 , - 2 )

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