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Solve the Problem f(p)=33p2+1,254p10,763f ( p ) = - 33 p ^ { 2 } + 1,254 p - 10,763

Question 110

Multiple Choice

Solve the problem.
-The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high, sales will drop. If the price is too low, the revenue brought in may not
Cover the cost to produce the shirts. After months of data collection, the sales team determines that
The monthly profit is approximated by f(p) =33p2+1,254p10,763f ( p ) = - 33 p ^ { 2 } + 1,254 p - 10,763 , where p is the price per shirt
And f p is the monthly profit based on that price. Find the price that generates the maximum profit
And find the maximum profit.


A) p=$19p = \$ 19
f(p) =$1,150f ( p ) = \$ 1,150

B) p=$38p = \$ 38
f(p) =$10,763f ( p ) = \$ 10,763

C) p=$19p = \$ 19
f(p) =$24,976f ( p ) = \$ 24,976

D) p=$38p = \$ 38
f(p) =$1,150f ( p ) = \$ 1,150

Correct Answer:

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