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Find an Equation of the Circle with the Given Characteristics (0,12)( 0,12 )

Question 219

Multiple Choice

Find an equation of the circle with the given characteristics.
- (0,12) ( 0,12 ) and radius 6\sqrt { 6 }


A) x2+(y+12) 2=6x ^ { 2 } + ( y + 12 ) ^ { 2 } = \sqrt { 6 }
B) (y+12) 2=6( y + 12 ) ^ { 2 } = 6
C) (y12) 2=6( y - 12 ) ^ { 2 } = \sqrt { 6 }
D) x2+(y12) 2=6x ^ { 2 } + ( y - 12 ) ^ { 2 } = 6

Correct Answer:

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