Solved

Solve the Problem 3\sqrt { 3 } And Center in Quadrant IV

Question 99

Multiple Choice

Solve the problem.
-Write an equation of the circle that is tangent to both axes with radius 3\sqrt { 3 } and center in Quadrant IV.


A) (x+3) 2+(y3) 2=3( x + \sqrt { 3 } ) ^ { 2 } + ( y - \sqrt { 3 } ) ^ { 2 } = \sqrt { 3 }
B) (x3) 2+(y+3) 2=3( x - \sqrt { 3 } ) ^ { 2 } + ( y + \sqrt { 3 } ) ^ { 2 } = 3
C) (x3) 2+(y+3) 2=3( x - \sqrt { 3 } ) ^ { 2 } + ( y + \sqrt { 3 } ) ^ { 2 } = \sqrt { 3 }
D) (x+3) 2+(y3) 2=3( x + \sqrt { 3 } ) ^ { 2 } + ( y - \sqrt { 3 } ) ^ { 2 } = 3

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions