Write the Equation in Standard Form $( x - h ) ^ { 2 } + ( y - k ) ^ { 2 } = r ^ { 2 }$

Multiple Choice

Write the equation in standard form: $( x - h ) ^ { 2 } + ( y - k ) ^ { 2 } = r ^ { 2 }$ . Then, if possible, identify the center and radius of the circle. If the equation represents a degenerate case, give the solution set.
- $$x ^ { 2 } + y ^ { 2 } + 4 x + 8 y + 11 = 0$$

A) $( x + 2 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 9$ ; Center: $( - 2 , - 4 )$ ; Radius: 3
B) $( x + 2 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 0 ;$ Degenerate case (single point $) : \{ ( - 2 , - 4 ) \}$
C) $( x + 2 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 9$ ; Center: $( 2,4 )$ ; Radius: 3
D) $( x + 2 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = - 9$ ; Degenerate case: \{ \}