Amy, Jean, Keith, Tom, Susan, and Dave Have All Been $720 ; 24 ; \frac { 1 } { 30 }$

Multiple Choice

Amy, Jean, Keith, Tom, Susan, and Dave have all been invited to a birthday party. They arrive randomly andeach person arrives at a different time. In how many ways can they arrive? In how many ways can Jean arrivefirst and Keith last? Find the probability that Jean will arrive first and Keith will arrive last.

A) $720 ; 24 ; \frac { 1 } { 30 }$
B) $720 ; 15 ; \frac { 1 } { 48 }$
C) $120 ; 6 ; \frac { 1 } { 20 }$
D) $120 ; 10 ; \frac { 1 } { 12 }$