Given P Is True, Q Is True, and R Is$$[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }$$

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The Answer of Given P Is True, Q Is True, and R Is$$[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }$$

Given P Is True, Q Is True, and R Is $[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }$

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Given P Is True, Q Is True, and R Is [(∼p→r)∧(∼p∨q)]→r[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }[(∼p→r)∧(∼p∨q)]→r

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Given P Is True, Q Is True, and R Is $[ ( \sim \mathrm { p } \rightarrow \mathrm { r } ) \wedge ( \sim \mathrm { p } \vee \mathrm { q } ) ] \rightarrow \mathrm { r }$

Correct Answer:
Verified
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