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Factor Completely Using the Trial and Error Method to Factor 8z2+6z98 z ^ { 2 } + 6 z - 9

Question 22

Multiple Choice

Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
- 8z2+6z98 z ^ { 2 } + 6 z - 9


A) (4z3) (2z+3) ( 4 z - 3 ) ( 2 z + 3 )
B) (4z+3) (2z3) ( 4 z + 3 ) ( 2 z - 3 )
C) prime
D) (8z3) (z+3) ( 8 \mathrm { z } - 3 ) ( \mathrm { z } + 3 )

Correct Answer:

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