Solve the Problem $$\left\{ \begin{array} { c } 3 x + y = 14 \\12 x + 4 y = 56\end{array} \right.$$

Multiple Choice

Solve the problem.
- $$\left\{ \begin{array} { c } 3 x + y = 14 \\12 x + 4 y = 56\end{array} \right.$$

A) no solution; $\varnothing$
B) $\{ ( 0,14 ) \}$
C) $\{ ( 5 , - 1 ) \}$
D) infinitely many solutions; $\{ ( x , y ) \mid 3 x + y = 14 \}$ or $\{ ( x , y ) \mid 12 x + 4 y = 56 \}$