Solve Using Cramer's Rule $= 3.5 \mathrm {~m}$ , Length $= 6 \mathrm {~m}$

Multiple Choice

Solve using Cramer's Rule.
-The perimeter of a rectangle is 19 meters. If the width is doubled and the length is tripled, the perimeter is 50 meters. Determine the original width and length.

A) width $= 3.5 \mathrm {~m}$ , length $= 6 \mathrm {~m}$
B) width $= 8 \mathrm {~m}$ , length $= 17 \mathrm {~m}$
C) width $= 6 \mathrm {~m}$ , length $= 10 \mathrm {~m}$
D) width $= 7 \mathrm {~m}$ , length $= 12 \mathrm {~m}$