One Solution of a Polynomial Equation Is Given $$6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$$

Multiple Choice

One solution of a polynomial equation is given. Use synthetic division to find any remaining solutions.
- $$6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$$

A) $\frac { 1 } { 3 } , 2$
B) $\frac { 1 } { 3 } , \frac { 1 } { 3 }$
C) $- 2 , \frac { 1 } { 3 }$
D) $\pm \frac { 1 } { 3 }$