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The Half-Life of Titanium 45 Is $3.1$ Hours If the Formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 }$

Question 287

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The half-life of Titanium 45 is $3.1$ hours. If the formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 }$ gives the percent (as a decimal) remaining after time $t$ (in hours) , sketch $P$ versus t.
$The half-life of Titanium 45 is 3.1 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t. A) B) C) D)$

A)
$The half-life of Titanium 45 is 3.1 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t. A) B) C) D)$
B)
$The half-life of Titanium 45 is 3.1 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t. A) B) C) D)$
C)
$The half-life of Titanium 45 is 3.1 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t. A) B) C) D)$
D)
$The half-life of Titanium 45 is 3.1 hours. If the formula \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 } gives the percent (as a decimal) remaining after time t (in hours) , sketch P versus t. A) B) C) D)$

The Half-Life of Titanium 45 Is 3.13.13.1 Hours If the Formula P(t)=(12)t/3.1\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 }P(t)=(21​)t/3.1

Multiple Choice

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The Half-Life of Titanium 45 Is $3.1$ Hours If the Formula $\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { \mathrm { t } / 3.1 }$

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