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If $4900 Is Invested in an Account Earning 7% Annual n=ln20.07\mathrm { n } = \frac { \ln 2 } { 0.07 }

Question 231

Multiple Choice

If $4900 is invested in an account earning 7% annual interest compounded continuously, then the number of years that it takes for the amount to grow to $9800 is n=ln20.07\mathrm { n } = \frac { \ln 2 } { 0.07 } Find the number of years to the nearest tenth of a
Year.


A) 7.9 yr
B) 9.9 yr
C) 11.9 yr
D) 14.9 yr

Correct Answer:

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