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A Balloon in the Shape of a Sphere Is Deflating V(r)=43πr3V ( r ) = \frac { 4 } { 3 } \pi r ^ { 3 }

Question 83

Multiple Choice

A balloon in the shape of a sphere is deflating. Given that t represents the time, in minutes, since it began losing air, the radius of the balloon (in cm) is r(t) =23- t . Let the equation V(r) =43πr3V ( r ) = \frac { 4 } { 3 } \pi r ^ { 3 } represent the volume of a sphere of radius r . Find and interpret (Vr) (t) ( \mathrm { V } \circ \mathrm { r } ) ( \mathrm { t } )


A) (Vr) (t) =2343π(23t) 3( \mathrm { V } \circ \circ \mathrm { r } ) ( \mathrm { t } ) = 23 - \frac { 4 } { 3 } \pi ( 23 - \mathrm { t } ) ^ { 3 } ; This is the volume of the air lost by the balloon (in cm3) as a function of time (in minutes) .
B) (Vr) (t) =43π(23t) 3( \mathrm { V } \circ \mathrm { r } ) ( \mathrm { t } ) = \frac { 4 } { 3 } \pi ( 23 - \mathrm { t } ) ^ { 3 } ; This is the volume of the air lost by the balloon (in cm3) as a function of time (in minutes) .
C) (Vr) (t) =43π(23t) 3( V \circ r ) ( t ) = \frac { 4 } { 3 } \pi ( 23 - t ) ^ { 3 } ; This is the volume of the balloon (in cm3 ) as a function of time (in minutes) .
D) (Vr) (t) =43π(t23) 3( \mathrm { V } \circ \mathrm { r } ) ( \mathrm { t } ) = \frac { 4 } { 3 } \pi ( \mathrm { t } - 23 ) ^ { 3 } ; This is the volume of the balloon (in cm3 ) as a function of time (in minutes) .

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