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The Height H of a Ball Thrown Is h(x)=2x0.08x2h ( x ) = 2 x - 0.08 x ^ { 2 }

Question 218

Multiple Choice

The height h of a ball thrown is given by h(x) =2x0.08x2h ( x ) = 2 x - 0.08 x ^ { 2 } where x is the horizontal distance traveled and both measurements are in feet. At what horizontal distances will the height of the ball be more than 9 ft ? (Round distances to the nearest tenth of a foot, if necessary.)


A) 0ft<x<5.9ft or 19.1ft<x<25ft0 \mathrm { ft } < \mathrm { x } < 5.9 \mathrm { ft } \text { or } 19.1 \mathrm { ft } < \mathrm { x } < 25 \mathrm { ft }
B) 0ft<x<19.1ft0 \mathrm { ft } < \mathrm { x } < 19.1 \mathrm { ft }
C) 5.9ft<x<25ft5.9 \mathrm { ft } < \mathrm { x } < 25 \mathrm { ft }
D) 5.9ft<x<19.1ft5.9 \mathrm { ft } < \mathrm { x } < 19.1 \mathrm { ft }

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