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The Distance an Object Is from the Ground After Being h(t)=16.1t2+5.7t+770h ( t ) = - 16.1 t ^ { 2 } + 5.7 t + 770

Question 291

Multiple Choice

The distance an object is from the ground after being tossed from a hot air balloon 770 feet in the air is a function of time and given by h(t) =16.1t2+5.7t+770h ( t ) = - 16.1 t ^ { 2 } + 5.7 t + 770 where h is height in feet and t is the number of seconds
The object has been in the air. Find h(5.5) and explain its meaning.


A) 314.33 feet; After the object has been in the air 5.5 seconds, it is 314.33 feet above the ground.
B) 712.80 feet; After the object has been in the air 712.80 seconds, it is 5.5 feet above the ground.
C) 251.63 feet; After the object has been in the air 5.5 seconds, it is 251.63 feet above the ground.
D) 712.80 feet; After the object has been in the air 5.5 seconds, it is 314.33 feet above the ground.

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