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For the Equation, Determine the Constants a and B That x(x+2)(x2)=A(x+2)+B(x2)\frac { x } { ( x + 2 ) ( x - 2 ) } = \frac { A } { ( x + 2 ) } + \frac { B } { ( x - 2 ) }

Question 329

Multiple Choice

For the equation, determine the constants A and B that make the equation an identity.
- x(x+2) (x2) =A(x+2) +B(x2) \frac { x } { ( x + 2 ) ( x - 2 ) } = \frac { A } { ( x + 2 ) } + \frac { B } { ( x - 2 ) }


A) A=12, B=12\mathrm { A } = - \frac { 1 } { 2 } , \mathrm {~B} = \frac { 1 } { 2 }
B) A=12,B=1A = \frac { 1 } { 2 } , B = 1
C) A=12, B=12\mathrm { A } = \frac { 1 } { 2 } , \mathrm {~B} = \frac { 1 } { 2 }
D) A=1, B=12\mathrm { A } = 1 , \mathrm {~B} = \frac { 1 } { 2 }

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