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Solve the Equation for Solutions Over the Interval [0 [0,2π)[ 0,2 \pi )

Question 144

Multiple Choice

Solve the equation for solutions over the interval [0, [0,2π) [ 0,2 \pi ) ) . Write solutions as exact values or to four decimal places, as
appropriate.
-The area of a triangle is given by
A=12absinC\mathrm { A } = \frac { 1 } { 2 } \mathrm { ab } \sin \mathrm { C } \text {, }
where a\mathrm { a } and b\mathrm { b } are the lengths of two of the sides and C\mathrm { C } is the included angle. If A=28\mathrm { A } = 28 in. 2,a=9in2 , \mathrm { a } = 9 \mathrm { in } ., b=8in\mathrm { b } = 8 \mathrm { in } ., and C\mathrm { C } is an acute angle, what must C\mathrm { C } be? Give your answer in degrees to the nearest hundredth.


A) 128.94128.94 ^ { \circ }
B) 51.0651.06 ^ { \circ }
C) 25.5325.53 ^ { \circ }
D) No such triangle exists.

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