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-If an Object Is Propelled Upward from a Height

Question 133

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-If an object is propelled upward from a height of 112 feet at an initial velocity of 96 feet per second, then its height after tt seconds is given by the equation h(t) =16t2+96t+112h ( t ) = - 16 t ^ { 2 } + 96 t + 112 . After how many seconds does the object hit the ground?


A) 6.0sec6.0 \mathrm { sec }
B) 3.5sec3.5 \mathrm { sec }
C) 7sec7 \mathrm { sec }
D) 11sec11 \mathrm { sec }

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